2t^2-50=30t

Solution for 2t^2-50=30t equation:

2t^2-50=30t

We move all terms to the left:

2t^2-50-(30t)=0

a = 2; b = -30; c = -50;
Δ = b2-4ac
Δ = -302-4·2·(-50)
Δ = 1300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1300}=\sqrt{100*13}=\sqrt{100}*\sqrt{13}=10\sqrt{13}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-10\sqrt{13}}{2*2}=\frac{30-10\sqrt{13}}{4}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+10\sqrt{13}}{2*2}=\frac{30+10\sqrt{13}}{4}
$